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 Post subject: CH_2005 (and anybody else)
PostPosted: Tue Apr 15, 2003 8:46 am 
Glow Ball
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Joined: Tue Feb 02, 1999 7:00 pm
Posts: 23
Do you know the 8-bit binary values for the numbers 1 to 20? What would they be?

00000001 = 1
00000010 = 2

but here's where I lose it - lol didn't take long, eh? Which of these is number 3

00000100 = ?
00000011 = ?

And on up to twenty. Thanks.

--------

While I'm here, does anybody have any particularly favorite math equations? I don't mean to solve, tho it could be, but just cuz there's something about them you like. We all know

E = mc<sup>2</sup>

or

a<sup>2</sup> = b<sup>2</sup> plus c<sup>2</sup>

or

y = mx plus b

I don't know how to make symbols or I'd try pye <font face="Symbol">p</font>r<sup>2</sup>. Could probably use theta, omega and stuff like that too.

By the way, this is for a track ;-)

<font size=+2 face=Wingdings>J</font>

edit. note to self. Look up that big ugly thing that solves quadratic equations. LOL, it'll fill a whole billboard, hehehe

<font size=1>Edited by Phineus (15-04-2003)</font>


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 Post subject:
PostPosted: Tue Apr 15, 2003 9:00 am 
http://www.computerhope.com/binhex.htm http://www.pccomputernotes.com/numbering/numbering04.htm http://www.unics.uni-hannover.de/nhtcapri/mathematics.html http://www.sosmath.com/tables/tables.html


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 Post subject:
PostPosted: Tue Apr 15, 2003 9:00 am 
You Gonna Eat That?
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Location: Nebraska
My head just exploded after reading "8-bit Binary"

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 Post subject:
PostPosted: Tue Apr 15, 2003 9:51 am 
Glow Ball
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Joined: Tue Feb 02, 1999 7:00 pm
Posts: 23
LOL, tell me about RF.

Anyway. Thanks, Link Image

00000000 = 0
00000001 = 1
00000010 = 2
00000011 = 3

00000100 = 4
00000101 = 5
00000110 = 6
00000111 = 7

00001000 = 8
00001001 = 9
00001010 = 10
00001011 = 11

00001100 = 12
00001101 = 13
00001110 = 14
00001111 = 15

00010000 = 16
00010001 = 17
00010010 = 18
00010011 = 19

00010100 = 20


Those last two have some nice looking equations... Zero to infinity looks kind funky.

<table cellpadding="0" cellspacing="0"><tr><td align="center">∞
<big><big><big>∑</big></big></big><small>
n<small> </small>=<small> </small>0</small></td><td>a<sub>n</sub><sup> </sup></td></tr></table>




<font size=1>Edited by Phineus (15-04-2003)</font>


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 Post subject:
PostPosted: Tue Apr 15, 2003 10:20 am 
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Posts: 695
Location: USA and Proud of it.
ax²+bx+c=0
x=(-b±(b²-4ac)^(1/2))/(2a)

ok a bit about number systems:
i'll use a truck analogy. You know on your truck u have an odometer. The odomeer has some wheels with digits on them. The on on the right moves. when it hit's 9 the one next to it moves 1 spot and then it goes back to 0, imagine an odometer where each wheel has only 2 symbols on it (1/0)
0000
0001
0010
0011
0100
0101
0110
0111
see?
we only count in base 10 cause we have ten fingers. If we had 8 fingers we would count in octal.
1
2
3
4
5
6
7
10
11
12
13
14
15
16
17
20
etc.
just remember in base 2 there are 2 symbols and in base 8 there are 8 symbols.

e^(i(pi)) = -1

pi = 3.14159265359...
you could have pi going all around the track :) that would be cool. Just search the net and u can easily find more digits than ever could be cared for


if i think of more i'll post

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 Post subject:
PostPosted: Tue Apr 15, 2003 10:36 am 
Glow Ball
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Joined: Tue Feb 02, 1999 7:00 pm
Posts: 23
x=(-b±(b²-4ac)^(1/2))/(2a)

Ah ha, that's the one I was thinking of.

And pi all around sounds hilarious. There's no way but I'll have to do something with it all the same. Thanks.


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 Post subject:
PostPosted: Tue Apr 15, 2003 10:39 am 
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Location: USA and Proud of it.
d=r*t
r=d/t
c/d=(pi)

Image

r=v/a

x^n + y^n <> z^n where x,y,z are ints and n is an int greater than 2



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 Post subject:
PostPosted: Tue Apr 15, 2003 10:41 am 
mtm<sup>2</sup> = ∞


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 Post subject:
PostPosted: Wed Apr 16, 2003 4:40 am 
Glow Ball
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Joined: Tue Feb 02, 1999 7:00 pm
Posts: 23
<center>
<IMG SRC="http://rhinoseros.com/~forum/pics/mtm2infinity.jpg" border=0></center>

Once you've said that, there's only one thing left to say...

Quote:
Press any key other than Ctrl,Shft,Alt,win,PrintScrn/SysRq,ScrollLock, Pause/Break,NumLock,Insert,CapsLock,any strange buttons along the top of your keyboard, and that wierd key with a mouse and a menu on it to continue.


<font size=+2 face=Wingdings>J</font>


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 Post subject:
PostPosted: Wed Apr 16, 2003 6:35 am 
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<font size=+99 face=Wingdings>J</font>

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 Post subject:
PostPosted: Wed Apr 16, 2003 2:43 pm 
>> My head just exploded after reading "8-bit Binary"

lol
No warning, just kablooey. Too funny. Image


>> we only count in base 10 cause we have ten fingers. If we had 8 fingers we would count in octal.

eight fingers, ten digits. Image


>> you could have pi going all around the track Image

clever!

∞ is a crazy 8


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 Post subject:
PostPosted: Wed Apr 16, 2003 5:23 pm 
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Location: carmel, california, usa
man, if i werent failing algebra ab, mabye i would understand all of this<font size=+2 face=Wingdings>K</font>

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 Post subject:
PostPosted: Thu Apr 17, 2003 1:03 pm 
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Actually finding out the binary is very easy. You just need to use the Windows Calculator Image

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"In my restless dreams, I see that town, Silent Hill..." - Mary, Silent Hill 2


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 Post subject:
PostPosted: Thu Apr 17, 2003 1:37 pm 
Glow Ball
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Posts: 23
Oh, sure, now he tells us.


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 Post subject:
PostPosted: Thu Apr 17, 2003 7:33 pm 
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Well i wanted to see how you guys give your best first Image

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"In my restless dreams, I see that town, Silent Hill..." - Mary, Silent Hill 2


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 Post subject:
PostPosted: Fri Apr 18, 2003 12:42 am 
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ok here's binary:
128 64 32 16 8 4 2 1
thats just about it
to write a number
(34) <random number i pulled
do i need a 128 ? no
do i need a 64 ? no
do i need a 32 ? yes
do i need a 16 ? no
do i need an 8 ? no
do i need a 4 ? no
do i need a 2 ? yes
do i need a 1 ? no
no,no,yes,no,no,no,yes,no
00100010b = 34d

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<font size=1>Edited by ch_2005 (18-04-2003)</font>


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 Post subject:
PostPosted: Fri Apr 18, 2003 1:12 am 
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Joined: Thu Mar 02, 2000 2:01 pm
Posts: 539
Location: Phoenix, AZ
Think of this way...
Reading a binary number Right to Left, starting with 1, each place to the left is double the place to it's right.

take a simple 4 bit code.

8's 4's 2's 1's

1 0 0 0 = 8
1 0 0 1 = 9


The highest DECIMAL number you can get with a 4 digit binary = 15.
All 4 bits on = 8+4+2+1 = 15
BUT it's called "16-bit" because 0 counts as a valid "state" and counted.

If you need a bigger number, add another place to the left by doubling the number to it's right.

The next place would be 16's with a max decimal number of 31
BUT of course called "32-bit"

Processores use millions of transistors that are either turned on (a 1) or off (a zero).
Binary is how we read and inturpet it.
Hence why you see computer measurements use the logical extension of those incruments...
16 bit 32 bit 256MB etc.
They just another place to the left of the binary code.




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<IMG SRC="http://vales.com/sigs/KC.gif" border=0>
It's all how you look at things ©¿©¬


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 Post subject:
PostPosted: Fri Apr 18, 2003 1:27 am 
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Location: Phoenix, AZ
Not exactly math, but logic is fun too.

iLenCount = len(Aurl)
For i = 1 To iLenCount
cTemp = mid(Aurl, i, 1)
If cTemp = "/" Then
JPerCount = JPerCount + 1
End If
next

If JPerCount > 1 then
isURL = True
End If


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<IMG SRC="http://vales.com/sigs/KC.gif" border=0>
It's all how you look at things ©¿©¬


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 Post subject:
PostPosted: Fri Apr 18, 2003 7:32 am 
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0-15 isnt called 16-bit, it has 16 values but it's 4-bit
i.e. 8-bit color isnt 8 colors it's 256: 0-255 1+2+4+8+16+32+64+128=255

16bit processors have 16 wire cables cause each wire is a bit:
a byte is 8 bits
16 bit processors work with 2 byte words
0000h-FFFFh

<hr>
iLenCount = len(Aurl)
For i = 1 To iLenCount
cTemp = mid(Aurl, i, 1)
If cTemp = "/" Then
JPerCount = JPerCount + 1
End If
next

If JPerCount > 1 then
isURL = True
End If
<hr>
huh?

wouldnt:

if instr(aurl,"/",1) then isURL = true

work?

plus just cause somthing has a / in it doesnt mean it's a URL
http:// means that it's a URL


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 Post subject:
PostPosted: Fri Apr 18, 2003 7:48 am 
Glow Ball
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Joined: Tue Feb 02, 1999 7:00 pm
Posts: 23
You guys and your vbscript Image

isURL = urlCheck(Aurl) ;

perl rules, lol


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